SOLUTION: Jacob started biking to the coffee shop traveling 9 mph, after some time the bike got a flat so Jacob walked the rest of the way, traveling 2 mph. If the total trip to the coffee s

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: Jacob started biking to the coffee shop traveling 9 mph, after some time the bike got a flat so Jacob walked the rest of the way, traveling 2 mph. If the total trip to the coffee s      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1076517: Jacob started biking to the coffee shop traveling 9 mph, after some time the bike got a flat so Jacob walked the rest of the way, traveling 2 mph. If the total trip to the coffee shop took 9 hours and it was 60 miles away, how long did Jacob travel at each speed?
Found 2 solutions by josgarithmetic, ankor@dixie-net.com:
Answer by josgarithmetic(39626) About Me  (Show Source):
You can put this solution on YOUR website!
                  SPEED      TIME      DISTANCE
BIKE               9          b          9b
WALK               2          w          2w
Total                         9          60


w=9-b
-
9b%2B2w=60
9b%2B2%289-b%29=60
9b%2B18-2b=60
7b=60-18
7b=42
highlight%28b=6%29-----Hours by bike

highlight%28w=3%29-------hours walking

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Jacob started biking to the coffee shop traveling 9 mph, after some time the bike got a flat so Jacob walked the rest of the way, traveling 2 mph.
If the total trip to the coffee shop took 9 hours and it was 60 miles away, how long did Jacob travel at each speed?
:
let b = time spent biking
then
(9-b) = time spent walking
:
Write a distance equation, dist = speed * time
bike dist + walk dist = 60 mi
9b + 2(9-b) = 60
9b + 18 - 2b = 60
9b - 2b = 60 - 18
7b = 42
b = 42/7
b = 6 hrs spend biking
then
9 - 6 = 3 hrs spent walking
:
:
:
Confirm this, find that actual dist for each
9(6) = 54 mi
2(3) = 6 mi
--------------
total dist 60 mi