SOLUTION: A person wishes to build a rectangular fence that will enclose an area of 317 square feet. The width
of the fence is to be 3 feet less than twice its length. Set up and solve
Question 1076500: A person wishes to build a rectangular fence that will enclose an area of 317 square feet. The width
of the fence is to be 3 feet less than twice its length. Set up and solve an algebraic equation to find the
dimensions of the fence to the nearest tenth of
a foot. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! length is x
width is 2x-3
x(2x-3)=317
2x^2-3x-317=0
x=(1/4)(3+/- sqrt (9+2536); sqrt(2545)=50.447
x=53.447/4 or 13.361 or 13.4 feet length
and 23.724 feet width or 23.7 feet
their product is 318.92 ft^2
using three decimal places, 13.361*23.724=316.98 ft^2
