|
Question 1076487: Use the following: 2/3x+y=16 and kx+3y=48
For what values of k does the linear system below have:
a) infinite solutions?
b) one solution?
c) no solution?
Found 2 solutions by ikleyn, Boreal:
Answer by ikleyn(52873)   (Show Source):
You can put this solution on YOUR website! .
2/3x + y = 16
kx + 3y = 48
For what values of k does the linear system below have:
a) infinitely many solutions? - At k = 2. Then the equations and right hand sides are proportional, and the system is DEPENDENT.
b) one solution? - At any other value of k =/= 2.
c) no solution? - There is NO such a value of k.
Answer by Boreal(15235)  (Show Source):
You can put this solution on YOUR website! (2/3)x+y=16
kx+3y=48
if kx=2, then 2x+3y=48 and multiplying the top by 3, 2x+3y=48, the same.
Therefore k=2 for infinite solutions.
The slope of the first is -2/3, and slope intercept form is -2x/3+16
the slope of the second is -(1/3)k and slope intercept form is -k/3+16
For k equal to any other number than 2, there will be one point of intersection.
For no solution, the two lines have to be parallel, and the line kx+3y=48 becomes 3y=-kx+48 and
y=-(k/3)+16. The y-intercept doesn't change with k, so there is no value where the lines are parallel without being the same line.
|
|
|
| |
