You can put this solution on YOUR website! The sum of three numbers is 9
a + b + c = 91
the first number is nine more than the second
a = b + 9
or
b = a - 9
the third number is two times the first
c = 2a
what are the numbers
Using the first equation, replace b with (a - 9); replace c with 2a
a + (a-9) + 2a = 91
4a = 91 + 9
4a = 100
a = 25 is the first number
then
b = 25 - 9
b = 16 is the 2nd number
and
c = 2(25)
c = 50 is the 3rd number
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See if that checks out
25 + 16 + 50 = 91
