SOLUTION: If the sides of a square are shortened by 4 cm, the area becomes 36 cm. find the length of a side of the original square.

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: If the sides of a square are shortened by 4 cm, the area becomes 36 cm. find the length of a side of the original square.      Log On


   



Question 1076357: If the sides of a square are shortened by 4 cm, the area becomes 36 cm. find the length of a side of the original square.
Found 2 solutions by Boreal, josmiceli:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
x^2 is area of original square
(x-4)^2 is new square=36 cm^2
x^2-8x+16-36
x^2-8x-20-0
(x+2)(x-10)=0
x=10 cm was the original square's side ANSWER
The new one is 4 less or 6, with area 36 cm^2.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +s+ = a side of the original square
+%28+s+-+4+%29%2A%28+s+-+4+%29+=+36+
+s%5E2+-+8s+%2B+16+=+36+
+s%5E2+-+8s+-20+=+0+
+%28+s+-+10+%29%2A%28+s+%2B+2+%29+=+0+ ( by looking at it )
+s+=+10+ ( can't use the negative solution )
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The sides of the original square are 10 cm
check:
+%28+s+-+4+%29%2A%28+s+-+4+%29+=+36+
+%28+10+-+4+%29%2A%28+10+-+4+%29+=+36+
+6%2A6+=+36+
OK