SOLUTION: x^3y^2=t^4/w solve for y

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Question 107628: x^3y^2=t^4/w solve for y
Found 2 solutions by Fombitz, MathLover1:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E3y%5E2=t%5E4%2Fw
%28cross%28x%5E3%29y%5E2%29%2Fcross%28x%5E3%29=t%5E4%2F%28wx%5E3%29 Divide both sides by x%5E3.
y%5E2=t%5E4%2F%28wx%5E3%29
sqrt%28y%5E2%29=sqrt%28t%5E4%2F%28wx%5E3%29%29 Take the square root of both sides.
y=t%5E2%2Fsqrt%28wx%5E%283%29%29 or
y=t%5E2w%5E%28-1%2F2%29x%5E%28-3%2F2%29

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
+x%5E3y%5E2=t%5E4%2Fw…….. solve for+y

y%5E2=%28t%5E4%2Fw%29%2Fx%5E3+.........we can write x%5E3 as x%5E3%2F1, then

y%5E2=%28t%5E4%2Fw%29%2F%28x%5E3%2F1%29+.........since
the quatient of two fractions (%28a%2Fb%29%2F%28c%2Fd%29 is ad%2Fbc, we will have

y%5E2=t%5E4%2F%28wx%5E3%29+........now find sqrt of both sides

sqrt%28y%5E2%29+=+sqrt%28t%5E4%2Fwx%5E3%29
or sqrt%28y%5E2%29+=+sqrt%28t%5E4%29%2Fsqrt%28wx%5E3%29

y+=+t%5E2%2Fx%28sqrt%28wx%29%29