SOLUTION: The length of a rectangle is 29 centimeters less than six times its width. Its area is 42 square centimeters. Find the dimensions of the rectangle.
Algebra ->
Quadratic Equations and Parabolas
-> SOLUTION: The length of a rectangle is 29 centimeters less than six times its width. Its area is 42 square centimeters. Find the dimensions of the rectangle.
Log On
Question 1076230: The length of a rectangle is 29 centimeters less than six times its width. Its area is 42 square centimeters. Find the dimensions of the rectangle. Answer by jorel1380(3719) (Show Source):
You can put this solution on YOUR website! Let w be the width of the rectangle. Then its length is 6w-29. So:
w(6w-29)=42
6w²-29w-42=0
(6w+7)(w-6)=0
w=6 or -7/6
Using the positive value for w, we get the dimensions of the rectangle to be 6 x 7 cms. ☺☺☺☺
