SOLUTION: In mixing a weed-killing solution, a 35% solution of the chemical is mixed with a 90% solution to get 55 L of a 60% solution. How much of each solution is needed. How many liters o
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-> SOLUTION: In mixing a weed-killing solution, a 35% solution of the chemical is mixed with a 90% solution to get 55 L of a 60% solution. How much of each solution is needed. How many liters o
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Question 1076156: In mixing a weed-killing solution, a 35% solution of the chemical is mixed with a 90% solution to get 55 L of a 60% solution. How much of each solution is needed. How many liters of the 35% solution is needed in the mixture? Answer by jorel1380(3719) (Show Source):
You can put this solution on YOUR website! Let n be the amount of 35% solution. Then the amount of 90% solution would be 55-n. So:
.35n+.9(55-n)=.6(55)
49.5-0.55n=33
0.55n=16.5
n=30
You need 30L of 35% solution; and 25L of 90% solution. ☺☺☺☺
