SOLUTION: A recent study found that the average life expectancy of a person living in Africa is 53 years with a a standard deviation of 7.5 years. If a person in Africa is selected at random
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Question 1076150: A recent study found that the average life expectancy of a person living in Africa is 53 years with a a standard deviation of 7.5 years. If a person in Africa is selected at random, what is the probability that the person will die before the age of 60? Assume normal distribution. Answer by rothauserc(4718) (Show Source):
You can put this solution on YOUR website! you calculate the z-score for the person aged 60
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z-score = (60 - 53) / 7.5 = 0.9333
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check the table of normal distribution z-scores
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Probability ( X < 60 ) = 0.8238
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