SOLUTION: Rohan mixed a 20% acid solution with an 80% acids solution to obtain 120 liters of a solution that is 50% acid. How much of each solution must be used to achieve the desired mixtur
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-> SOLUTION: Rohan mixed a 20% acid solution with an 80% acids solution to obtain 120 liters of a solution that is 50% acid. How much of each solution must be used to achieve the desired mixtur
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Question 1076131: Rohan mixed a 20% acid solution with an 80% acids solution to obtain 120 liters of a solution that is 50% acid. How much of each solution must be used to achieve the desired mixture? Found 2 solutions by ikleyn, Alan3354:Answer by ikleyn(52855) (Show Source):
The equation is
0.2*x + 0.8*(120-x) = 0.5*120,
where "x" is the volume of the 20% acid solution.
Simplify and solve for x:
0.2x + 96 -0.8x = 60,
-0.6x = 60 - 96,
-0.6x = - 36,
x = = 60.
Answer. 60 liters of the 20% solution and 120-60 = 60 liters of the 80% solution.
