SOLUTION: Match the corresponding function formula with each function when h(x) = 3x + 2 and g(x) = 2^x.
1. k(x) = 2^(x) + 3x + 2
2. k(x) = 2^(x) - 3x - 2
3. k(x) = (3x)2^(-x) + 2^(-x +
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-> SOLUTION: Match the corresponding function formula with each function when h(x) = 3x + 2 and g(x) = 2^x.
1. k(x) = 2^(x) + 3x + 2
2. k(x) = 2^(x) - 3x - 2
3. k(x) = (3x)2^(-x) + 2^(-x +
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Question 1076083: Match the corresponding function formula with each function when h(x) = 3x + 2 and g(x) = 2^x.
1. k(x) = 2^(x) + 3x + 2
2. k(x) = 2^(x) - 3x - 2
3. k(x) = (3x)2^(-x) + 2^(-x + 1)
4. k(x) = 2^(3x + 2)
5. k(x) = 2^(x) * (3x + 2)
6. k(x) = 3 * (2^(x)) + 2
a. k(x) = (h ÷ g)(x)
b. k(x) = (g - h)(x)
c. k(x) = (g + h)(x)
d. k(x) = (h ∘ g)(x)
e. k(x) = (g * h)(x)
f. k(x) = (g ∘ h)(x)
Please but them in this format: (number)-(letter) Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Match the corresponding function formula with each function when h(x) = 3x + 2 and g(x) = 2^x.
1. k(x) = 2^(x) + 3x + 2 = (g+h)x
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2. k(x) = 2^(x) - 3x - 2 = (g-h)x
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3. k(x) = (3x)2^(-x) + 2^(-x + 1) = (h*g)x
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4. k(x) = 2^(3x + 2) = (goh)(x))
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etc.
Cheers,
Stan H.
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5. k(x) = 2^(x) * (3x + 2)
6. k(x) = 3 * (2^(x)) + 2
a. k(x) = (h ÷ g)(x)
b. k(x) = (g - h)(x)
c. k(x) = (g + h)(x)
d. k(x) = (h ∘ g)(x)
e. k(x) = (g * h)(x)
f. k(x) = (g ∘ h)(x)
Please put them in this format: (number)-(letter)