SOLUTION: Shauna had an English average of 84%. On her next test she scored 96%, and this raised her overall average to 86%. On the test after this, her average fell to 85%. What was her mar

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: Shauna had an English average of 84%. On her next test she scored 96%, and this raised her overall average to 86%. On the test after this, her average fell to 85%. What was her mar      Log On


   



Question 1076070: Shauna had an English average of 84%. On her next test she scored 96%, and this raised her overall average to 86%. On the test after this, her average fell to 85%. What was her mark on the last test
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
Let n be the number of tests Shauna has taken. Then:
84n+96=86(n+1)
2n=96-86=10
n=5
Let m be the score on her last test. Then:
5*86+m=85*6
430+m=510
m=80 as her mark on the last test. ☺☺☺☺