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Question 1076010: You need to rent a car and are debating between 2 companies. Company A has a plan that charges 0.50 per mile. Company B charges a 20 dollar fee plus .25 per mile. How many miles would you have to drive for both plans to cost the same amount?
I had created both equations. Company A- 0.5m and Company B- 20+0.25m and set them equal to each other but I don't know if I am right on that step, but I solved it and got 5, which doesn't make the equations equal.
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! You need to rent a car and are debating between 2 companies. Company A has a plan that charges 0.50 per mile. Company B charges a 20 dollar fee plus .25 per mile. How many miles would you have to drive for both plans to cost the same amount?
I had created both equations. Company A- 0.5m and Company B- 20+0.25m and set them equal to each other but I don't know if I am right on that step, but I solved it and got 5, which doesn't make the equations equal.
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Cost = 0.50*m = 20 + 0.25m
You did the right thing, but how did you get 5 miles?
0.50*m = 20 + 0.25m
Solve for m.
Multiply by 4 to eliminate fractions.
2m = 80 + m
m = 80 miles
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