SOLUTION: I don't understand this problem: If N is the first of six consecutive odd numbers and 42 is the average of these numbers, find N.

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Question 1075979: I don't understand this problem: If N is the first of six consecutive odd numbers and 42 is the average of these numbers, find N.
Found 3 solutions by stanbon, ikleyn, MathTherapy:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
If N is the first of six consecutive odd numbers and 42 is the average of these numbers, find N.
Let N = 2x-5
2nd:: 2x-3
3rd:: 2x-1
4th:: 2x+1
5th:: 2x+3
6th:: 2x+5
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Average = 12x/6 = 2x = 42
x = 21
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Ans: N = 2x-5 = 42-5 = 37
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Cheers,
Stan H.
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Answer by ikleyn(52914) About Me  (Show Source):
You can put this solution on YOUR website!
.
If 42 is the average of six consecutive odd numbers, then these numbers are

42-1, 42+1, 42-3, 42+3, 42-5, 42+5   (non-ordered),  or

37, 39, 41, 43, 45 and 47  (ordered by ascend).

N = 37.


Answer by MathTherapy(10557) About Me  (Show Source):
You can put this solution on YOUR website!

I don't understand this problem: If N is the first of six consecutive odd numbers and 42 is the average of these numbers, find N.
Since N is the 1st number, then others are: N + 2, N + 4, N + 6, N + 8, and N + 10

We then get: 

matrix%281%2C3%2C+%286N+%2B+30%29%2F6%2C+%22=%22%2C+42%29 

6N + 30 = 252 ------- Cross-multiplying

6N = 222

N, or 1st number = highlight_green%28matrix%281%2C3%2C+222%2F6%2C+or%2C+37%29%29

That's all!! Nothing CONFUSING and/or COMPLEX!