A container holds 15 pennies, 8 nickels, and 10 dimes.
You will randomly select two coins without replacement.
-->Fill in the probabilities on a tree diagram.
Here's the probability tree:
There are 9 outcomes. The probability of each outcome
is gotten by multiplying the probabilities along the two
lines from the beginning of the tree to the outcome.
For outcome #1, prob = (15/33)(14/32) which reduces to 35/176
For outcome #2, prob = (15/33)(8/32) which reduces to 5/44
For outcome #3, prob = (15/33)(10/32) which reduces to 25/176
For outcome #4, prob = (8/33)(15/32) which reduces to 5/44
For outcome #5, prob = (8/33)(7/32) which reduces to 7/132
For outcome #6, prob = (8/33)(10/32) which reduces to 5/66
For outcome #7, prob = (10/33)(15/32) which reduces to 25/176
For outcome #8, prob = (10/33)(8/32) which reduces to 5/66
For outcome #9, prob = (10/33)(9/32) which reduces to 15/176
--> How many ways can you select the coins?There are 9 outcomes
--> How many ways can you select exactly 1 nickel?That's either outcome #2, #4, #6, or #8, that's 4 ways
--> What is the probability that you select 2 pennies?
That's outcome #1, probability = 35/176
--> What is the probability that you select a dime and then a penny?
That's outcome #7, probability = 25/176
You got the hardest two right, and missed the two easy ones. lol
Edwin
