SOLUTION: Pick four cards from a regular deck without replacement. What is the probability that you get exactly two hearts at the first and fourth cards? I have tried two different ways

Algebra ->  Probability-and-statistics -> SOLUTION: Pick four cards from a regular deck without replacement. What is the probability that you get exactly two hearts at the first and fourth cards? I have tried two different ways      Log On


   

Question 1075565: Pick four cards from a regular deck without replacement. What is the probability that you get exactly two hearts at the first and fourth cards?
I have tried two different ways 1st I came up with
1/2704
1/117 also incorrect.... Any suggestions??????


Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
For the 1st card, there are +13+ ways to get a heart
so P(H[1]) = +13%2F52+
For the 2nd card, there are +39+ ways to NOT get a heart
so P(X[2]) = +39%2F51+
For the 3rd card, there are +38+ ways to NOT get a heart
so P(x[3]) = +38%2F50+
For the 4th card, there are +12+ ways to get a heart
so P(H[4]) = +12%2F49+
--------------------------
You want all of these, so multiply probabilities
+%28+13%2F52+%29%2A%28+39%2F51+%29%2A%28+38%2F50+%29%2A%28+12%2F49+%29+=+231192%2F6497400+
+231192%2F6497400+=+.03558+
Definitely get a 2nd opinion on this!!