SOLUTION: Log(3x+1)-log2=log11
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Question 1075511
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Log(3x+1)-log2=log11
Found 3 solutions by
jorel1380, MathTherapy, josgarithmetic
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Answer by
jorel1380(3719)
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log(3x-1)-log 2=log 11
log(3x-1)/log 2=log 11
(3x-1)/2=11
3x-1=22
3x=23
x=23/3 ☺☺☺☺
Answer by
MathTherapy(10555)
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Log(3x+1)-log2=log11
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Answer by
josgarithmetic(39625)
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Log(3x+1)-log2=log11