SOLUTION: Jose has 22 coins totaling $4.10. If all of the 22 coins are either nickels or quarters, how many of each coin does he have?

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Question 1075486: Jose has 22 coins totaling $4.10. If all of the 22 coins are either nickels or quarters, how many of each coin does he have?
Answer by ikleyn(52817) About Me  (Show Source):
You can put this solution on YOUR website!
.
Your equation is

5N + 25*(22-N) = 410   cents.


5N + 550 - 25N = 410,

-20N = 410 - 550,

-20N = -140,

N = %28-140%29%2F%28-20%29 = 7.


Answer.  7 nickels and 22-7 = 15 quarters.


There is entire bunch of lessons on coin problems
    - Coin problems
    - More Coin problems
    - Solving coin problems without using equations
    - Kevin and Randy Muise have a jar containing coins
    - Typical coin problems from the archive
    - More complicated coin problems
    - Solving coin problems mentally by grouping without using equations
    - Santa Claus helps solving coin problem
in this site.

You will find there the lessons for all levels - from introductory to advanced,
and for all methods used - from one equation to two equations and even without equations.

Read them and become an expert in solution of coin problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Coin problems".