Question 1075330: Find the equation of the curve for which y'' = 6 if the curve is tangent to the line y = 8x at (2, 16). Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! y''=6
y'=6x + C
y=3x^2+some value of x
y=3x^2-4x has a first derivative of 6x-4 which is 8 when evaluated at x=2
but the function equals 16 when x=2, so the constant term is 12
y=3x^2-4x+12