SOLUTION: Please solve and state restrictions {{{(n^2+3n+2)/(n^2+5n+6)}}} minus {{{(2n)/(n+3)}}}

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Question 1075326: Please solve and state restrictions
%28n%5E2%2B3n%2B2%29%2F%28n%5E2%2B5n%2B6%29 minus %282n%29%2F%28n%2B3%29

Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
common denominator is (n+3)(n+2)
The numerator will be n^2+3n+2-2n(n+2)= -n^2-n+2=-(n^2+n-2)=-(n+2)(n-1)
The (n+2) will cancel numerator and denominator,
so the answer is
-(n-1)/(n+3)
Check with n=4
30/42-8/7=-18/42 or -3/7
-(3)/7