SOLUTION: Simplify and state restrictions {{{(n-6)/(n^2+11n+24)}}}{{{"÷"}}}{{{ (n+1)/(n+3)}}} {{{(n-6)/(n^2+11n+24)}}}{{{"÷"}}}{{{ (n+1)/(n+3)}}}

Algebra ->  Rational-functions -> SOLUTION: Simplify and state restrictions {{{(n-6)/(n^2+11n+24)}}}{{{"÷"}}}{{{ (n+1)/(n+3)}}} {{{(n-6)/(n^2+11n+24)}}}{{{"÷"}}}{{{ (n+1)/(n+3)}}}       Log On


   



Question 1075322: Simplify and state restrictions
%28n-6%29%2F%28n%5E2%2B11n%2B24%29%22%F7%22+%28n%2B1%29%2F%28n%2B3%29
%28n-6%29%2F%28n%5E2%2B11n%2B24%29%22%F7%22+%28n%2B1%29%2F%28n%2B3%29

Found 2 solutions by Boreal, Edwin McCravy:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
(n-6)/(n+8)(n+3)*(n+3)/(n+1), invert when you divide and multiply
the (n+3) cancel
(n-6)/(n+8)(n+1)
This does not exist at x=-8, -3 or -1, the last because you would be dividing by 0.

Answer by Edwin McCravy(20062) About Me  (Show Source):
You can put this solution on YOUR website!
Simplify and state restrictions
%28n-6%29%2F%28n%5E2%2B11n%2B24%29%22%F7%22+%28n%2B1%29%2F%28n%2B3%29

We factor the denominator on the first fraction:

%28n-6%29%2F%28%28n%2B8%29%28n%2B3%29%29%22%F7%22+%28n%2B1%29%2F%28n%2B3%29

None of the denominators can be 0, so

we must restrict the denominators

n+8≠0,   n+3≠0
  n≠-8,    n≠-3

However we must not divide by 0, so the numerator
of what we are dividing by must not equal 0 either

So the numerator of the second fraction also cannot
be 0, for then the fraction that we are dividing by
would be 0, and we cannot divide by zero.

n+1≠0
  n≠-1

So the restrictions are n≠-8, n≠-3, and n≠-1

To finish the problem, we invert the second fraction
and multiply:

%28n-6%29%2F%28%28n%2B8%29%28n%2B3%29%29%22%D7%22+%28n%2B3%29%2F%28n%2B1%29

and cancel:

%28n-6%29%2F%28%28n%2B8%29%28cross%28n%2B3%29%29%29%22%D7%22+%28cross%28n%2B3%29%29%2F%28n%2B1%29

%28n-6%29%2F%28%28n%2B8%29%28cross%28n%2B3%29%29%29%22%D7%22+%28cross%28n%2B3%29%29%2F%28n%2B1%29


%28n-6%29%2F%28%28n%2B8%29%28n%2B1%29%29, n≠-8, n≠-3, n≠-1

Edwin