SOLUTION: Find an integer where twice the square of the number is 11 more then 9 times the number

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Question 1075312: Find an integer where twice the square of the number is 11 more then 9 times the number
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
number is x
2x^2-11=9x
2^2-9x-11=0
(2x-11)(x+1)=0
x=-1 ANSWER; the other root isn't an integer.
Twice the square of -1 is 2
2 is 11 more than 9(-1) or -9.