SOLUTION: Suppose that 68% of the employees of a company participate in the company’s medical savings program. Let x be the number of employees who participate in the program in a random sam
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Question 1075235: Suppose that 68% of the employees of a company participate in the company’s medical savings program. Let x be the number of employees who participate in the program in a random sample of 50 employees. Find the mean and standard deviation of x. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! The mean is np=50*0.68=34
The variance is np(1-p)=34*0.32=10.88
The sd is the sqrt (var)=3.30
