SOLUTION: 1. A medical researcher says that less than 25% of U.S. adults are smokers. In a random sample of 200 adults, 18.5% say that they are smokers. At , is there enough evidence to re

Algebra ->  Probability-and-statistics -> SOLUTION: 1. A medical researcher says that less than 25% of U.S. adults are smokers. In a random sample of 200 adults, 18.5% say that they are smokers. At , is there enough evidence to re      Log On


   



Question 1075160: 1. A medical researcher says that less than 25% of U.S. adults are smokers. In a random sample of 200 adults, 18.5% say that they are smokers. At , is there enough evidence to reject the researcher’s claim?
Make a decision regarding?

Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
Ho: p=0.25
Ha: pNE 0.25
Alpha=0.05 P{reject Ho|ho true)
test stat 1 sample proportion z=(0.185-0.25)/sqrt (p*(1-p)/n)
Reject if |z|>1.96
z=-0.065)/sqrt {0.25*0.75/200}
=-0.065/0.0306
=2.12
Reject Ho. The true value is not 25% (two way test).