SOLUTION: Find two consecutive odd numbers such that two-fifths of the smaller exceeds two- ninth of the larger by 4

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Question 1075143: Find two consecutive odd numbers such that two-fifths of the smaller exceeds two- ninth of the larger by 4
Answer by Alan3354(69443) About Me  (Show Source):
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Find two consecutive odd numbers such that two-fifths of the smaller exceeds two- ninth of the larger by 4
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2n/5 = 2(n+2)/9 + 4
18n = 10n + 20 + 180
8n = 200
n = 25
--> 25 & 27