SOLUTION: The function f, defined for x ∈ R, x>0, is such that: f'(x) =x^2 - 2+x^-2 Given that f(3)=0, find f(x). Also prove that f is an increasing function.

Algebra ->  Test -> SOLUTION: The function f, defined for x ∈ R, x>0, is such that: f'(x) =x^2 - 2+x^-2 Given that f(3)=0, find f(x). Also prove that f is an increasing function.       Log On


   



Question 1075016: The function f, defined for x ∈ R, x>0, is such that:
f'(x) =x^2 - 2+x^-2
Given that f(3)=0, find f(x). Also prove that f is an increasing function.

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Integrating,
f%28x%29=x%5E3%2F3-2x-1%2Fx%2BC
So when x=3,
0=%283%29%5E3%2F3-2%283%29-1%2F3%2BC
0=9-6-1%2F3%2BC
0=9%2F3-1%2F3%2BC
C=-8%2F3
highlight%28f%28x%29=x%5E3%2F3-2x-1%2Fx-8%2F3%29
.
.
.
Since the derivative is always positive in x%3E0, the function is increasing.
.