Question 1075000: 2\sqrt(3x+3)=12
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! 2/sqrt(3x+3)=12; NOTE: I am assuming the radical is a denominator.
1/sqrt(3x+3)=6
sqrt(3x+3)=(1/6) by cross multiplying
3x+3=1/36 by squaring
108x+108=1, by multiplying by 36
108x=-107
x=-0.991
2/sqrt(0.027778)=12
If this is a product, then one would divide both sides by 2, square both sides, and solve for x.
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