SOLUTION: A rectangle has a length that is 6 more than its width. If the width is doubled, and the length tripled, the resulting perimeter is 66 square inches larger than that of the origina

Algebra ->  Rectangles -> SOLUTION: A rectangle has a length that is 6 more than its width. If the width is doubled, and the length tripled, the resulting perimeter is 66 square inches larger than that of the origina      Log On


   

Question 1074864: A rectangle has a length that is 6 more than its width. If the width is doubled, and the length tripled, the resulting perimeter is 66 square inches larger than that of the original.
Found 2 solutions by ikleyn, josgarithmetic:
Answer by ikleyn(52888) About Me  (Show Source):
You can put this solution on YOUR website!
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Perimeter IS NOT measured in square inches.


Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
IF you meant PERIMETER, then the amount larger would become 66 INCHES.

ORIGINAL RECTANGLE
Dimensions w+6, and w

INCREASED DIMENSIONS RECTANGLE
Dimensions 3(w+6), and 2w

Amount of increase, 66 INCHES:
2%2A3%28w%2B6%29%2B2%2A2w-2%28w%2B6%29-2w=66
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Original Rectangle Dimensions: system%28w=7%2Cand%2CL=13%29