SOLUTION: Find the margin of error if p = 71% and n = 100. Round to four decimal places.

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Question 1074823: Find the margin of error if p = 71% and n = 100. Round to four decimal places.
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
the margin of error is z*sqrt {(p)(1-p)/n}
If we use 95% CI, which isn't stated here, 1.96*sqrt (0.71*0.29/100)=0.0889
The sqrt term is the standard error of the mean. The margin of error is +/-0.0889