Question 1074781: A recent study found that children who watched a cartoon with food advertising ate, on
average, 28.5 grams of Goldfish crackers as compared to an average of 19.7 grams of Goldfish crackers for
children who watched a cartoon without food advertising. Although there were 118 children in the study,
neither the sample size in each group nor the sample standard deviations were reported. Suppose that there
were 59 children in each group, and the sample standard deviation for those children who watched the food
ad was 8.6 grams and the sample standard deviation for those children who did not watch the food ad was
7.9 grams
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! This is a t-test to see if the grams eaten of Goldfish crackers is significant between the two groups, I think. It isn't clear.
Assuming all the assumptions for such a test are valid.
t df=116, 0.975=1.96; reject for |t|>1.96. The sample sizes are large enough so that a normal distribution could be used.
SE = sqrt ((s1^2/n1+(s2^2/n2))=sqrt (1.254+1.058)=1.521
t= difference in means/SE=8.8/1.521=5.79
Strongly significant with p=6.25 X 10^(-8)
|
|
|
