SOLUTION: Please help me solve this word problem. The length of a rectangle is twice the width. A second rectangle, which is 8 cm longer and 3 cm narrower than the first rectangle, has a per

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Question 1074657: Please help me solve this word problem. The length of a rectangle is twice the width. A second rectangle, which is 8 cm longer and 3 cm narrower than the first rectangle, has a perimeter of 154cm. Find the dimensions of each rectangle. Make a sketch.
Found 2 solutions by ikleyn, josgarithmetic:
Answer by ikleyn(52851) About Me  (Show Source):
You can put this solution on YOUR website!
.
Sorry,

it is YOU who must make a sketch.

I can solve this problem without making a sketch.

YOU must do it, and I do not need your instructions on how I should act to solve the problem.

Really.


Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
The first rectangle:
Using w for WIDTH, has dimensions according to description, w and 2w.


The second rectangle:
Following the description, this has dimensions w-3 and 2w+8.


Perimeter of 154 is given for the SECOND rectangle.
Using formula for perimeter of a rectangle,
highlight_green%282%282w%2B8%29%2B2%28w-3%29=154%29
SOLVE FOR w.


You can now find the dimensions of each rectangle.