SOLUTION: Solve the inequality. Graph your solution. 2y+7>11

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Question 107459This question is from textbook Pre-Algebra
: Solve the inequality. Graph your solution.
2y+7>11
This question is from textbook Pre-Algebra

Found 2 solutions by MathLover1, jim_thompson5910:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
2y%2B7%3E11.....move 7 to the right
2y+%3E+11+-+7
2y+%3E+4.....divide both sides by 2
y+%3E+2
graph as an equation y=2, and see that there are no x for what is y%3E2:
This inequality is a common "real life" constraint: only allowing y to be greater then 2. The line "y+=+0" is just the line parallel to x-axis, and we want the all positive values of y above the line. You need to dash the line in, because this isn't an "or equal to" inequality, so the "solution" of the system is the shaded part above the line.

Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
This equation defines a horizontal line. There is no X intercept. Y intercept is 2%2F1=2
graph%28+500%2C+500%2C+-10%2C+10%2C+2+-+10%2C+2%2B10%2C+2%2F1+%29+


Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

2y%2B7%3E11 Start with the given inequality


2y%3E11-7Subtract 7 from both sides


2y%3E4 Combine like terms on the right side


y%3E%284%29%2F%282%29 Divide both sides by 2 to isolate y



y%3E2 Divide

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Answer:
So our answer is y%3E2


Now let's graph the solution set


Start with the given inequality:

y%3E2

Set up a number line:
number_line%28500%2C-8%2C12%29 note: just replace the x with the variable you are working with


Now plot the point y=2 on the number line


number_line%28500%2C-8%2C12%2C+2%29


Now pick any test point you want, I'm going to choose y=0, and test the inequality y%3E2


0%3E2 Plug in y=0


Since this inequality is not true, we simply shade the entire portion that does not contain the point y=0 using the point y=2 as the boundary. This means we shade everything to the right of the point y=2 like this:
Graph of y%3E2 with the shaded region in blue
note: at the point y=2, there is an open circle. This means the point y=2 is excluded from the solution set.