SOLUTION: Solve for x: log(9x+1)-log(x^2-2)=log2

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Question 1074526: Solve for x: log(9x+1)-log(x^2-2)=log2
Answer by Alan3354(69443) About Me  (Show Source):
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Solve for x: log(9x+1)-log(x^2-2)=log2
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log((9x+1)/(x^2-2)) = log(2)
(9x+1)/(x^2-2) = 2
9x+1 = 2x^2 - 4
2x^2 - 9x - 5 = 0
(2x + 1)*(x - 5) = 0
x = -1/2, 5
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-1/2 is rejected, log(9x+1) is negative for x = -1/2