SOLUTION: An ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that th

Algebra ->  Probability-and-statistics -> SOLUTION: An ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that th      Log On


   



Question 1074516: An ordinary (fair) die is a cube with the numbers
1
through
6
on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.
Compute the probability of each of the following events:
Event
A
: The sum is greater than
5
.
Event
B
: The sum is an even number.
Write your answers as exact fractions.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
An ordinary (fair) die is a cube with the numbers
1 through 6 on the sides (represented by painted spots).
Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.
Compute the probability of each of the following events:
Event A
: The sum is greater than 5
Total sums:: 36
Total sums <= 5:: 1/1 ; 1/2 ; 1/3 ; 1/4
2/1 ; 2/2 ; 2/3
3/1 ; 3/2
4/1 ;
Ans:: (36-10)/36 = 13/18
-------------------
.
Event
B
: The sum is an even number.
Write your answers as exact fractions.
Ans: 18/36 = 1/2
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Cheers,
Stan H.
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