SOLUTION: Water is flowing into a conical reservoir 25.0 m deep and 10.0 m across the top, at a rate of 16.0 m3/min. How fast is the surface rising when the water is 10.0 m deep?

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Question 1074453: Water is flowing into a conical reservoir 25.0 m deep and 10.0 m across the top, at a rate of 16.0 m3/min. How fast is the surface rising when the water is 10.0 m deep?
Answer by Alan3354(69443) About Me  (Show Source):
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Water is flowing into a conical reservoir 25.0 m deep and 10.0 m across the top, at a rate of 16.0 m3/min. How fast is the surface rising when the water is 10.0 m deep?
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Assuming 10 m is the diameter, r = 5
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Vol = pi*r^2*h/3
Find r in terms of h:
For 0 <= h <= 25,
r/h = 5/25
r = h/5
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Vol+=+pi%2A%28h%5E2%2F25%29%2Ah%2F3+=+pi%2Ah%5E3%2F75
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dVol/dt = pi*h^2/25*dh/dt = 16
dh/dt = 400/(pi*h^2)
At h = 10,
dh/dt = 4/pi meters/minute