SOLUTION: How do I work log(x-1)-log(x+6)=log(x-2)-log(x+3)

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Question 1074423: How do I work log(x-1)-log(x+6)=log(x-2)-log(x+3)
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
log((x-1))-log((x+6))=log((x-2))-log((x+3))
log%28%28x-1%29%29-log%28%28x%2B6%29%29=log%28%28x-2%29%29-log%28%28x%2B3%29%29

Try to avoid forming rational expressions.

log%28%28x-1%29%29%2Blog%28%28x%2B3%29%29-log%28%28x%2B6%29%29=log%28%28x-2%29%29
log%28%28x-1%29%29%2Blog%28%28x%2B3%29%29=log%28%28x-2%29%29%2Blog%28%28x%2B6%29%29
log%28%28%28x-1%29%28x%2B3%29%29%29=log%28%28%28x-2%29%28x%2B6%29%29%29

Whatever the base used, as long as left and right sides are using the same base, then the expressions inside the log functions must be equal.

%28x-1%29%28x%2B3%29=%28x-2%29%28x%2B6%29
and you can probably handle the rest from here.