SOLUTION: I hope this is in the right category.
The monthly salaries in a company with 5000 employees are normally distributed. The mean salary is $3100 with a standard deviation of $700
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The monthly salaries in a company with 5000 employees are normally distributed. The mean salary is $3100 with a standard deviation of $700
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Question 1074409: I hope this is in the right category.
The monthly salaries in a company with 5000 employees are normally distributed. The mean salary is $3100 with a standard deviation of $700. What percentage of employees earn more than $2400 per month? How many employees earn more than $2400 per month? Answer by Theo(13342) (Show Source):
2400 is (3100 - 2400) / 700 = 1 standard deviation from the mean in a negative direction.
that makes the z-score equal to -1.
with z-scores, the mean is 0 and the z-score is the number of standard deviations away from the mean.
the formula is z = (x-m) / s
z is the z-score
x is the raw score
m is the mean
s is the standard deviation.
the formula becomes z = (2400 - 3100)/700 = -700/700 = -1
to find the percentage of employees that earn more than a z-score of -1, look up in the z-score table for a rate (rate = % / 100) to the left of a z-score of -1.
then take 1 minus that rate for a rate to the right of a z-score of -1.
if you used the table linked to below, you would have found the rate to the left of the z-score of -1 equal to .1587 and then gotten the rate to the right of the z-score of -1 equal to 1 - .1587 = .8413.