SOLUTION: Y=7x cuts the circle x^2+y^2=50 at A and B A in quadrant one . Find coordinates of A and B

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Question 1074391: Y=7x cuts the circle x^2+y^2=50 at A and B A in quadrant one . Find coordinates of A and B

Answer by ikleyn(52885) About Me  (Show Source):
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Substitute 7x instead of y into equation of the circle.


You will get 


x^2 + 49x^2 = 50  --->  50x^2 = 50,  x = +/-1.


Thus the point A is (x,y) = (1,7) in quadrant I.


The other point is (x,y) = (-1,-7) in quadrant III.