SOLUTION: Separate the number 28 into two parts such that the product of one part and the square of the other part is a maximum.
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Question 1074345: Separate the number 28 into two parts such that the product of one part and the square of the other part is a maximum. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Separate the number 28 into two parts such that the product of one part and the square of the other part is a maximum.
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f(x) = x^2*(28-x) = 28x^2 - x^3
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f'(x) = 56x - 3x^2 = 0
x = 0 --- Ignore
3x = 56
x = 56/3
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--> 56/3 and 28/3
