SOLUTION: How do I solve this non-linear system of equation? 6x^2+y^2=1 x^2+2y^2=13

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Question 1074087: How do I solve this non-linear system of equation?
6x^2+y^2=1
x^2+2y^2=13
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
6x^2 + y^2 = 1
x^2 +2y^2 =13
use elimination, multiply the 1st equation by 2
12x^2 +2y^2 = 2
x^2 + 2y^2 = 13
-------------------subtraction eliminates y^2, find x^2
11x^2 + 0 = -11
x^2 = -11/11
x^2 = -1
Find y, replace x^2 with -1 in the first equation
6(-1) + y^2 = 1
y^2 = 1 + 6
y^2 = 7
:
Check solution in the 2nd equation
-1 + 2(7) = 13
:
perhaps they wanted this
x^2 = -1
x =sqrt%28-1%29
x = i, (we know the i^2 = -1)
and
y = sqrt%287%29