SOLUTION: Two cyclists leave a city at the same​ time, one going east and the other going west. The west bound cyclist bikes at 3 mph faster than the east bound cyclist. After 5 hours
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Question 1074056: Two cyclists leave a city at the same time, one going east and the other going west. The west bound cyclist bikes at 3 mph faster than the east bound cyclist. After 5 hours they are 225 miles apart. How fast is each cyclist riding? Answer by ikleyn(52824) (Show Source):
Your equation is
5r + 5*(r+3) = 225.
5r + 5r + 15 = 225 ---> 10r = 210 ---> r = = 21.
Answer. The speed of the slower cyclist is 21 mph. The speed of the faster syclist is 21+3 = 24 mph.
