SOLUTION: If the sides of a square are decreased by 2 cm, the area is decreased by 36 cm2. What were the dimensions of the original square?

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: If the sides of a square are decreased by 2 cm, the area is decreased by 36 cm2. What were the dimensions of the original square?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 107404: If the sides of a square are decreased by 2 cm, the area is decreased by
36 cm2. What were the dimensions of the original square?

Found 2 solutions by checkley75, josmiceli:
Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
(X-2)^2=X^2-36
X^2-4X+4=X^2-36
-4X=-36-4
-4X=-40
X=-40/-4
X=10 CM ANSWER FOR THE ORIGINAL DIMENSIONS OF THE SQUARE.
PROOF:
(10-2)^2=10^2-36
8^2=100-36
64=64

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Call the original area A and let x = side of original square
So, for the original square, A+=+x%5E2
Now if x is decreased by 2, A is decreased by 36, so
A+-+36+=+%28x-2%29%5E2
but A+=+x%5E2, so
x%5E2+-+36+=+%28x-2%29%5E2
x%5E2+-+36+=+x%5E2+-+4x+%2B+4
4x+-+4+=+36
4x+=+40
x+=+10 cm
So, the original square was 10x10 and A = 100
check this
A+-+36+=+%28x-2%29%5E2
100+-+36+=+%2810-2%29%5E2
64+=+8%5E2
64+=+64 OK