SOLUTION: Could someone please explain to me how to work this type of problem. I have tried to figure it out and keep coming up with the wrong answer. Find the slope and y-intercept by wr

Algebra ->  Linear-equations -> SOLUTION: Could someone please explain to me how to work this type of problem. I have tried to figure it out and keep coming up with the wrong answer. Find the slope and y-intercept by wr      Log On


   



Question 107392: Could someone please explain to me how to work this type of problem. I have tried to figure it out and keep coming up with the wrong answer.
Find the slope and y-intercept by writing the equation in slope intercept form then graph,
-4x-3y=6
I am totally stuck on this one Please help.
Thank You

Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
Given the equation:
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-4x - 3y = 6
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The slope-intercept form of this equation will be in the form of:
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y = mx + b
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and in this form, m (the multiplier of x) is the slope and b (the constant) is the y-intercept.
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So to solve the problem you can work the given equation into the slope intercept form.
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Begin by getting rid of the -4x on the left side. Do this by adding +4x to both sides. When
you add +4x to the left side, it cancels the -4x and so on the left side the x-terms
disappear. On the right side, when you add +4x, the term +4x appears. So by adding +4x to
both sides the given equation becomes:
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-3y = +4x + 6
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Now solve this equation for y by dividing both sides by -3 (the multiplier of y on the
left side. When you do this division (both sides ... all terms) the left side becomes just
y and both terms on the right side are divided by -3.
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y+=+%284%2F-3%29x+%2B+6%2F-3+=+-%284%2F3%29x+-+2
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Therefore the equation is reduced to:
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y+=+-%284%2F3%29x+-+2
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Notice how this compares to the point-slope form. In this equation the multiplier of
x is -%284%2F3%29 and the multiplier of x is the slope. Therefore, the slope of the graph of
the given equation is -%284%2F3%29. And the constant term on the right side ... which is -2 ...
is the point on the y-axis where the graph crosses the y-axis.
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You can graph y+=+-%284%2F3%29x-2. This graph is the same as the graph of the original equation
you were given as a problem. The graph looks like this:
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graph%28600%2C600%2C-10%2C10%2C-10%2C10%2C+-%284%2F3%29x+-+2%29
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Hope this helps you to understand the problem.
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