| 
 
 
| Question 1073789:  Some functions that aren't invertible can be made invertible by restricting their domains. For example, the function x^2 is invertible if we restrict x to the interval [0,infinity), or to any subset of that interval. In that case, the inverse function is square root(x). (We could also restrict x^2 to the domain (-infinity,0], in which case the inverse function would be -sqrt(x)
 Similarly, by restricting the domain of the function f(x) = 2x^2-4x-5 to an interval, we can make it invertible. What is the largest such interval that includes the point x=0?Thank you.
 Answer by stanbon(75887)
      (Show Source): 
You can put this solution on YOUR website! Similarly, by restricting the domain of the function f(x) = 2x^2-4x-5 to an interval, we can make it invertible. What is the largest such interval that includes the point x=0? ------
 Find the turning point (vertex).
 It occurs where x = -b/(2a) = 4/(2(2)) = 1
 ------
 Since x = 0 is to the left of x = 1 the larger
 interval is (-oo,1)
 ------------
 Cheers,
 Stan H.
 ---------------
 | 
  
 | 
 |