SOLUTION: A car travels 816 mi. A second car, traveling 3 mph faster than the first car, makes the same trip in 1 h less time. Find the speed of each car.
first car .......... mph
second
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first car .......... mph
second
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Question 1073783: A car travels 816 mi. A second car, traveling 3 mph faster than the first car, makes the same trip in 1 h less time. Find the speed of each car.
first car .......... mph
second car ......... mph Answer by jorel1380(3719) (Show Source):
You can put this solution on YOUR website! Let n be the speed of the slower car. Then the faster car is going n+3. So:
816/n=816/(n+3) + 1
816(n+3)=816n+nē+3n
nē+3n-2448=0
(n+51)(n-48)=0
n=48 or -51
The first car travels at 48 mph; the second car travels at 51 mph. ☺☺☺☺
