Question 107372This question is from textbook Structure and Method
: I am working on charts and this particular question is giving me a hard time:
The length of a red rectangle is 15cm more than its width w. A blue rectangle, which is 5 cm wider and 2 cm shorter than the red one, has perimeter 72cm. Make a sketch of the rectangles expressing all dimensions in terms of w. Then find the dimensions of each rectangle.
This question is from textbook Structure and Method
Answer by elima(1433)   (Show Source):
You can put this solution on YOUR website! The length of a red rectangle is 15cm more than its width w. A blue rectangle, which is 5 cm wider and 2 cm shorter than the red one, has perimeter 72cm. Make a sketch of the rectangles expressing all dimensions in terms of w. Then find the dimensions of each rectangle.
Larger rectangular;
L=W+15
W=W
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smaller rectangular;
L=w+15-2
W=W+5
2(w+13)+2(w+5)=72
2w+26+2w+10=72
4w+36=72
4w=36
w=9
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Now we will plug the nine in for w, lets do the first one;
W=9
L=W+15
L=9+15=24
------------------------
w=W+5
w=9+5=14
l=w+13
l=9+13=22
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:)
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