Question 1073647:
Find the vertex of the graph of the quadratic function. Determine whether the graph opens upward or downward, find any intercepts, and sketch the graph.
f(x)=-x^2-2x+3
A. The vertex is:
B. The parabola opens downward or upward
C. The x-intercepts are:
D. The Y-intercepts are:
E; Graph
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Find the vertex of the graph of the quadratic function. Determine whether the graph opens upward or downward, find any intercepts, and sketch the graph.
f(x)=-x^2-2x+3
A. The vertex is:
x = -b/(2a) = 2/(-2) = -1
y = f(-1) = -1+2+3 = 4
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B. The parabola opens downward or upward
Down because a = -1
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C. The x-intercepts are:
Solve -x^2-2x+3 = 0
x^2 + 2x - 3 = 0
(x+3)(x-1) = 0
x = -3 or x = 1
Intercepts:: (-3,0) ; (1,0)
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D. The Y-intercepts are:
f(0) = -0^2-2*0+3 = 3
Intercept:: (0,3)
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E; Graph
Plot the points and sketch the parabola.
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Cheers,
Stan H.
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