SOLUTION: I need help solving a trigonometry equation with a given interval. solve the equation on the interval 0 is less than or equal to theta which is less than 2pin 4 sin theta+3=5

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Question 1073573: I need help solving a trigonometry equation with a given interval.
solve the equation on the interval 0 is less than or equal to theta which is less than 2pin
4 sin theta+3=5

Answer by ikleyn(52805) About Me  (Show Source):
You can put this solution on YOUR website!
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I need help solving a trigonometry equation with a given interval.
solve the equation on the interval 0 is less than or equal to theta which is less than 2pin
4 sin theta+3=5
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1.  Your writing is INCORRECT. Your interval is 0 <= theta < 2pi  (not 2pin).


2.  4%2Asin%28theta%29+%2B+3 = 5 ---->

    4%2Asin%28theta%29 = 5 -3 ----> 4%2Asin%28theta%29 = 2 ---->  sin%28theta%29 = 2%2F4  ---->  sin%28theta%29 = 1%2F2.


    In the given interval, the solutions are  x = pi%2F6  and  x = 5pi%2F6.