SOLUTION: Can someone please explain why choice D is correct and why choices A, B, C are incorrect? For a polynomial p(x), the value of p(3) is −2. Which of the following must be tr

Algebra ->  Functions -> SOLUTION: Can someone please explain why choice D is correct and why choices A, B, C are incorrect? For a polynomial p(x), the value of p(3) is −2. Which of the following must be tr      Log On


   



Question 1073398: Can someone please explain why choice D is correct and why choices A, B, C are incorrect?
For a polynomial p(x), the value of p(3) is −2. Which of the following must be true about p(x) ?
A) x−5 is a factor of p(x).
B) x−2 is a factor of p(x).
C) x+2 is a factor of p(x).
D) The remainder when p(x) is divided by x−3 is −2.

Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
Remainder Theorem. If x-3 were a factor of p(x), then the remainder would be 0; but it is not 0.

Answer by ikleyn(52788) About Me  (Show Source):
You can put this solution on YOUR website!
.
The statement D) is true.

The reference: The remainder theorem.


Theorem   (the remainder theorem)

   1. The remainder of division the polynomial  f%28x%29  by the binomial  x-a  is equal to the value  f%28a%29  of the polynomial. 

   2. The binomial  x-a  divides the polynomial  f%28x%29  if and only if the value of  a  is the root of the polynomial  f%28x%29,  i.e.  f%28a%29+=+0.

   3. The binomial  x-a  factors the polynomial  f%28x%29  if and only if the value of  a  is the root of the polynomial  f%28x%29,  i.e.  f%28a%29+=+0.

See the lesson
    - Divisibility of polynomial f(x) by binomial x-a
in this site.

This lesson is the part of the (free of charge) online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

under the topic "Divisibility of polynomial f(x) by binomial (x-a). The Remainder theorem".