SOLUTION: A fruit grower use two types of fertilizer in his orange grove, brand A and brand B. Each bag of brand A contains 9 pounds of nitrogen and 5 pounds of phosphoric acid. Each bag of
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-> SOLUTION: A fruit grower use two types of fertilizer in his orange grove, brand A and brand B. Each bag of brand A contains 9 pounds of nitrogen and 5 pounds of phosphoric acid. Each bag of
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Question 1073378: A fruit grower use two types of fertilizer in his orange grove, brand A and brand B. Each bag of brand A contains 9 pounds of nitrogen and 5 pounds of phosphoric acid. Each bag of brand B contains 8 pound of nitrogen and 6 pounds of phosphoric acid. Test indicate that the grove needs 770 pounds of nitrogen and 490 pounds of phosphoric acid. How many bags of each brand should be used to provide the required amounts of nitrogen and phosphoric acid.
I set up the equation with this:
9a + 8b=770
5a + 6b=490
I then took equation #2 and times it by 2, then subtracted equation #1 from equation #2...
Help at a loss.. Found 2 solutions by ikleyn, josgarithmetic:Answer by ikleyn(52813) (Show Source):
You have this system
9a + 8b = 770 (1)
5a + 6b = 490 (2)
Multiply eq(1) by 5 (both sides). Multiply eq(2) by 9 (both sides). You will get
45a + 40b = 3850 (1')
45a + 54b = 4410 (2')
Now subtract eq(1') from eq(2'). You will get
54b - 40b = 4410 - 3850, or
14b = 560 ---> b = = 40.
From this point please complete the solution on your own.
The method I used is called the "Elimination method".
Maybe try to eliminate terms of b.
8*3=24,and,6*4=24.
Here, subtract equation #2 from #1.
Now maybe you can find how to solve for b on your own. If you do this through Elimination, go back to the original system of equations and work from there.